写程序求1到100所有整数的和
printf(＂1到100的和为：d＂ sum)；// 输出累加器变量这段代码中，使用了for循环来遍历1到100的所有数字，并将它们累加到变量sum中。最后，使用printf用c语言写一个程序，计算并输出1到100之间所有正整数的和。#include <stdio.h> int main() { int sum = 0; for (int i = 1; i <= 100; i++) { sum += i; } printf(＂1
C语言程题解】A202-3-7-9-求1到100的和，用C语言求和，33.例：求和1至100,1.5_09奇数求和，谭浩强c语言程序设计例5.2用do while 语句求1-100的和bian xie C yu yan cheng xu qiu jie jie : ( 1 ) shu xue fang fa S = 1 + 2 + 3 + ……+ 9 8 + 9 9 + 1 00= ( 1 + 1 00) + ( 2 + 9 9 ) + ( 3 + 9 8 ) 4 9 + 5 2 ) + ( 5 0+ 5 1 ) = 1 01 * 5 0= 5 05 0( 2 ) C yu yan bian cheng # i n c l u d e & l t ; s t d i o . h & g t ; i n t m a i n ( ) { i n t s u m = 0; / / fu chu zhi f o r ( "
用c语言写一个程序，计算并输出1到100之间所有正整数的和。#include int main() { int sum = 0; for (int i = 1; i sum += i; } printf("1到100之间所有正整数的和为：%d\n", sum); return 0; } 这个程序的思路很简单，就是使用循环计算从1到100之间所有正整数的和。具体来说，我们定义一个变量sum 用来保存累加的结果，初始值为0。然后使用for 循环遍历从1到100之间的所有正整数，每次将当前的数加到sum 中。最后输出sum 的值即可。include<stdio.h> int main(){ int sum = 0 ; int number = 1 ; int i = 1 ; while (i <= 100 ) { sum = sum + number; number = number + 1 ; i = i + 1 ; } printf( " sum=%d " ,sum); return 0 ;}
p r i n t f ( ＂1 dao 1 00de he wei ：% d ＂, s u m ) ；/ / shu chu lei jia qi bian liang zhe duan dai ma zhong ，shi yong le f o r xun huan lai bian li 1 dao 1 00de suo you shu zi ，bing jiang ta men lei jia dao bian liang s u m zhong 。zui hou ，shi yong p r i n t f " # i n c l u d e & l t ; s t d i o . h & g t ; i n t m a i n ( ) { i n t s u m = 0; i n t n u m b e r = 1 ; i n t i = 1 ; w h i l e ( i & l t ; = 1 00) { s u m = s u m + n u m b e r ; n u m b e r = n u m b e r + 1 ; i = i + 1 ; } p r i n t f ( & q u o t ; s u m = % d & q u o t ; , s u m ) ; r e t u r n 0; }
写C语言程序求解解： (1)数学方法S = 1+2+3+……98+99+100 = (1+100) + (2+99) + (3+98)49+52) + (50+51) = 101 * 50 = 5050 (2)C语言程#include <stdio.h>int main(){ int sum = 0; // 赋初值for(yong c yu yan bian xie yi ge cheng xu ，ji suan bing shu chu 1 dao 1 00zhi jian suo you zheng zheng shu de he 。# i n c l u d e & l t ; s t d i o . h & g t ; i n t m a i n ( ) { i n t s u m = 0; f o r ( i n t i = 1 ; i & l t ; = 1 00; i + + ) { s u m + = i ; } p r i n t f ( ＂1
yong c yu yan bian xie yi ge cheng xu , ji suan bing shu chu 1 dao 1 00zhi jian suo you zheng zheng shu de he 。# i n c l u d e i n t m a i n ( ) { i n t s u m = 0; f o r ( i n t i = 1 ; i s u m + = i ; } p r i n t f ( & q u o t ; 1 dao 1 00zhi jian suo you zheng zheng shu de he wei : % d \ n & q u o t ; , s u m ) ; r e t u r n 0; } zhe ge cheng xu de si lu hen jian dan , jiu shi shi yong xun huan ji suan cong 1 dao 1 00zhi jian suo you zheng zheng shu de he 。ju ti lai shuo , wo men ding yi yi ge bian liang s u m yong lai bao cun lei jia de jie guo , chu shi zhi wei 0。ran hou shi yong f o r xun huan bian li cong 1 dao 1 00zhi jian de suo you zheng zheng shu , mei ci jiang dang qian de shu jia dao s u m zhong 。zui hou shu chu s u m de zhi ji ke 。C yu yan bian cheng ti jie 】A 2 02 - 3 - 7 - 9 - qiu 1 dao 1 00de he ，yong C yu yan qiu he ，3 3 . an li ：qiu he 1 zhi 1 00, 1 . 5 _ 09 qi shu qiu he ，tan hao qiang c yu yan cheng xu she ji li 5 . 2 yong d o w h i l e yu ju qiu 1 - 1 00de he "