x平方加x减1等于0因式分解
ke yi xian yin shi fen jie x ² + 2 x - 3 = ( x + 3 ) ( x - 1 ) suo yi （x + 3 ）( x - 1 ) ≥ 0suo yi x ≤ - 3 huo x ≥ 1 xiao bian hai wei nin zheng li le yi xia nei rong ，ke neng dui nin ye you bang zhu ：x de ping fang da yu deng yu 2 x de jie ji nin hao ！qing chun qi de " x 1 = - 1 0huo x 2 = 9 。jie da guo cheng ru xia ：（1 ）x de ping fang jia x jia 1 deng yu 9 1 ke yi xie cheng fang cheng ：x ² + x + 1 = 9 1 ( 2 ) yi xiang de ：x ² + x - 9 0= 0( 3 ) yin shi fen jie de ：（x + 1 0）( x - 9 ) = 0( 4 ) x + 1 0= 0huo x - 9 = 0( "
x1=-10或x2=9。解答过程如下：（1）x的平方加x加1等于91可以写成方程：x²+ x+1=91(2)移项得：x²+ x-90=0(3)因式分解得：（x+10）x-9)=0(4)x+10=0或x-9=0(x & q u o t ; + x = 1 x & q u o t ; + x / 2 + x / 2 + 1 / 4 = 1 + 1 / 4 x ( x + 1 / 2 ) + 1 / 2 ( x + 1 / 2 ) = 5 / 4 ( x + 1 / 2 ) & q u o t ; - 5 / 4 = 0[ x + 1 / 2 + ( gen hao 5 ) / 2 ] [ x + 1 / 2 - ( gen hao 5 ) / 2 ] = 0[ x + ( 1 + gen hao 5 ) / 2 ] [ x + ( 1 - gen hao 5 ) / 2 ] = 0
可以先因式分解x²+2x-3=(x+3)(x-1)所以（x+3）x-1)≥0所以x≤-3或x≥1 小还为您整理了以下内容，可能对您也有帮助：x的平方大于等于2x的解集您好！青春期的X平方+X-1=0用公式法x1=(-1+根号5)/2,x2=(-1-根号5)/2, 所以： X平方+X-1 =[x-(-1+根号5)/2][x-(-1-根号5)/2]
yuan fang cheng de jie wei X 1 = 0, X 2 = 1 。dang ran ，jie yi yuan er ci fang cheng ye ke yi li yong gong shi fa jin xing qiu jie 。qi ta hui da X de ping fang jian qu X deng yu ling she 乄er shu ze ：shu de ping fang yi shu er O 。nei rong sheng ming ：ben " x" + x = 1 x" + x/2 + x/2 + 1/4 = 1 + 1/4 x( x + 1/2 ) + 1/2( x + 1/2 ) = 5/4 ( x + 1/2 )" - 5/4 = 0 [ x + 1/2 + (根号5)/2 ][ x + 1/2 - (根号5)/2 ] = 0 [ x + (1 + 根号5)/2 ][ x + (1 - 根号5)/2 ] = 0
原方程的解为X1=0,X2=1。当然，解一元二次方程也可以利用公式法进行求解。其他回答X的平方减去X等于零设乄二，则：，的平方一，二O。内容声明：本X ping fang + X - 1 = 0yong gong shi fa x 1 = ( - 1 + gen hao 5 ) / 2 , x 2 = ( - 1 - gen hao 5 ) / 2 , suo yi : X ping fang + X - 1 = [ x - ( - 1 + gen hao 5 ) / 2 ] [ x - ( - 1 - gen hao 5 ) / 2 ]